\documentclass[11pt,b4j,dvipdfmx,landscape,twocolumn,papersize]{jsarticle}
% furikana.sty	http://xymtex.com/fujitas2/texlatex/index.html#tategumi
\usepackage{ascmac,bm,amssymb,furikana}
\usepackage[deluxe]{otf}
\usepackage{graphicx,color}
%\usepackage{qrcode}
%\usepackage[pdfpagemode=FullScreen,setpagesize=false]{hyperref}
%\usepackage[pdfstartview={XYZ null null 1.75},setpagesize=false]{hyperref}
\usepackage{hyperref,pxjahyper}
\usepackage{tikz}
\usetikzlibrary{calc}
%\usetikzlibrary{intersections,patterns,angles,backgrounds,positioning}

%\AtBeginDvi{\special{pdf:pagesize width 364mm height 257mm}}
\textwidth=330truemm \textheight=226truemm \columnseprule=0pt
\topmargin=-24truemm \oddsidemargin=-8truemm

\hypersetup{% Oct 1 2023
	pdftitle={数学授業プリント},
	pdfauthor={gbb60166@gmail.com},
	pdfsubject={https://unilab.gbb60166.jp/math_ia/math_ia.htm}
	}

\newenvironment{nidan}{\begin{minipage}[t]{.225\textwidth}}{\end{minipage}}
%\def\nidangumi#1#2{\begin{nidan}{#1}\end{nidan}\quad%
%\begin{nidan}{#2}\end{nidan}}
\newcommand{\nidangumi}[2]{\begin{nidan}{#1}\end{nidan}\quad%
\begin{nidan}{#2}\end{nidan}}

% ■■■ 0より大きいときはdvipdfmxで印刷用PDFを作ることを想定（答えはプリント
% 下部に出力される）
%        0 のときはdvipdfmxでデジタル教材用PDFを作ることを想定（答えは問題の
% すぐ横に赤で出力され、後でOneNoteで黒く塗りつぶし）
\def\make_pdf_with_insatsu{1}

\everymath{\displaystyle}
\parindent=0zw \columnsep=3zw
\lineskiplimit=1ex \normallineskiplimit=\lineskiplimit 
\lineskip=\lineskiplimit \normallineskip=\lineskiplimit

\newcounter{toi} \newcounter{subtoi}[toi]
\newcounter{subsubtoi}[subtoi]

\def\toi{\refstepcounter{toi}\par          % 問
  \makebox[2zw][r]{\Large\ajKaku{\value{toi}}\hspace{0.5zw}}%
  \hangindent=2zw}

\def\subtoi{\refstepcounter{subtoi}\par    % 小問
  \makebox[3.4zw][r]{\ajKakko{\value{subtoi}}\hspace{1zw}}%
  \hangindent=3.4zw}

\def\subsubtoi{\refstepcounter{subsubtoi}\par    % 小小問
  \makebox[4.2zw][r]{\ajMaru{\value{subtoi}}\hspace{1zw}}%
  \hangindent=4.2zw}

\ifnum\make_pdf_with_insatsu>0
	\def\kotae#1{\relax}
\else
	\def\kotae#1{\hfill \textcolor{red}{\footnotesize\gtfamily\bfseries\(\boldsymbol{#1} \)}}
\fi

\newcommand{\Slash}[1]{\ooalign{\hfil\kern-0.2em／\hfil\crcr$#1$}}
\pagestyle{empty}

\makeatletter
\def\hooklen#1#2{\settowidth{\@tempdima}{\(#1\)}
%\advance\@tempdima by.3ex
% ↑ 数式モードで式の前後に入るスペースを制御したかったが、
%    難しいのでやめた。段々難解なコードになっているのでやめた方がよい？
\hbox to\@tempdima{\hfil \(#2\)\hfil}}
\newcommand{\myleqq}{\mathrel{\mathpalette\gl@align<}}
\newcommand{\mygeqq}{\mathrel{\mathpalette\gl@align>}}
\newcommand{\gl@align}[2]{\lower.6ex\vbox{\baselineskip\z@skip\lineskip\z@
	\ialign{$\m@th#1\hfil##\hfil$\crcr#2\crcr=\crcr}}}
\makeatother


% ■■ 変数 yurika を定義する	2021 Feb 19
\newif\ifyurika
% \yurikatrue は有理化された答えが表示（\yurikafalse は有理化されない答え）
\yurikatrue
%\yurikafalse

\begin{document}
%
%  ===========================以下本文===============================
%
\def\namae{%
%{\Large\gtfamily\bfseries 数学I \quad 期末考査対策プリント}\hfill
{\Large\gtfamily\bfseries 数学I \quad 三角比の復習}\hfill
年\hskip8ex 組\hskip8ex 号 \hskip5ex

\hfill 
\underline{氏名\rule[-2ex]{0cm}{6ex}\hskip30ex}}

\namae

\vskip-3ex

{\large\gtfamily\bfseries ■　\kana{\(\mathstrut{\boldsymbol{\sin}}\)}{サイン}，
\kana{\(\mathstrut{\boldsymbol{\cos}}\)}{コサイン}，
\kana{\(\mathstrut{\boldsymbol{\tan}}\)}{タンジェント}}

\begin{center}
\begin{minipage}[t]{0.45\textwidth}
\begin{shadebox}

$\bullet$ \(\sin\mbox{A}={縦 \over 斜め} \)
\hskip6zw
$\bullet$ \(\cos\mbox{A}={横 \over 斜め} \)
\hskip6zw
$\bullet$ \(\tan\mbox{A}={\,縦\, \over 横} \)

\unitlength=1mm

\begin{tikzpicture}[>=stealth]% 筆記体を書く　ｓｉｎ
\draw(0.5,0)--(2.5,1.2)--(2.5,0)--(0.5,0)--cycle;
\draw(2.3,0.2) rectangle (2.5,0);
\draw[->,red,line width=2pt,line join=round](0,0)
	.. controls (1,0.3) and (2,1)
	.. (3,2)
	.. controls (3,0.5) and (3,-0.1) .. (2.4,0);
\draw(0.4,-0.2) node{$A$};
\end{tikzpicture}
%
\hspace*{2.4zw}
%
\begin{tikzpicture}[>=stealth]% 筆記体を書く　ｃｏｓ
\draw(0.5,0)--(2.5,1.2)--(2.5,0)--(0.5,0)--cycle;
\draw(2.3,0.2) rectangle (2.5,0);
\draw[->,red,line width=2pt,line join=round](3,1.5)
	..controls (1,1.7) and (-0.2,0.5) .. (0,0)
	..controls (0.2,-0.5) and (2,-0.5) .. (3,-0.1);
\draw(0.4,0.2) node{$A$};
\end{tikzpicture}
%
\hspace*{2.4zw}
%
\begin{tikzpicture}[>=stealth]% 筆記体を書く　ｔａｎ
\draw(0.5,0)--(2.5,1.2)--(2.5,0)--(0.5,0)--cycle;
\draw(2.3,0.2) rectangle (2.5,0);
\draw[->,red,line width=2pt,line join=round] (0,-0.2) ..controls (1,-0.2) and (3.2,-0.5) .. (3.2,0.3)
	..controls (3.2,0.7) and (3.2,1.5) .. (3.2,2);
\draw[red,line width=2pt,line join=round] (3.6,-0.2) ..controls (3.1,0) and (3.2,0.2) .. (3.2,1.9);
\draw[red,line width=2pt] (2.8,1.5)--(3.6,1.5);
\draw(0.4,0.2) node{$A$};
\end{tikzpicture}


\end{shadebox}
\end{minipage}
\end{center}



\begin{center}
\begin{minipage}[t]{0.3\textwidth}
\begin{shadebox}

$\bullet$　三平方の定理

\begin{center}

\( \mbox{{\Huge\gtfamily\bfseries 斜め}}^2=○^2+△^2\)

\end{center}

\vspace*{0.5ex}

\end{shadebox}
\end{minipage}
\end{center}

\unitlength=1mm

\toi 次の直角三角形ABCで，\(\sin A，\cos A，\tan A\)の値を求めなさい。


\nidangumi{\subtoi
\begin{tikzpicture}[rotate=-150, scale=0.6, baseline=(current bounding box.north)]
\coordinate [label=below:{\footnotesize A}] (A) at (3,2.65);
\coordinate [label=right:{\footnotesize B}] (B) at (0,0);
\coordinate [label=left:{\footnotesize C}] (C) at (3,0);
\draw (A)--(B)--(C)--cycle;
%%\draw (2.5,0)--(2.5,0.5)--(3,0.5);
\draw (C)++(-0.3,0)-- ++(0,0.3)-- ++(0.3,0);
\draw(1.2,1.5) node{\footnotesize $4$};
\draw(1.5,-0.2) node{\footnotesize $3$};
\end{tikzpicture}\kotae{
\ifyurika
	{3\over4},{\sqrt{7}\over4},{3\sqrt{7}\over7}
\else
	{3\over4},{\sqrt{7}\over4},{3\over\sqrt{7}}
\fi}
}
{\subtoi
\begin{tikzpicture}[rotate=-80, scale=0.5, baseline=(current bounding box.north)]
\coordinate [label=left:{\footnotesize A}] (A) at (0,0);
\coordinate [label=right:{\footnotesize B}] (B) at (3,5);
\coordinate [label=below:{\footnotesize C}] (C) at (3,0);
\draw (A)--(B)--(C)--cycle;
%\draw (2.5,0)--(2.5,0.5)--(3,0.5);
\draw (C)++(-0.3,0)-- ++(0,0.3)-- ++(0.3,0);
\draw(1.5,-0.5) node{\footnotesize $3$};
\draw(3.3,2.5) node{\footnotesize $5$};
\end{tikzpicture}\kotae{
\ifyurika
	{5\sqrt{34}\over34},{3\sqrt{34}\over34},{5\over3}
\else
	{5\over\sqrt{34}},{3\over\sqrt{34}},{5\over3}
\fi}
}
\vfill


\ifnum\make_pdf_with_insatsu>0
	\rotatebox{180}{{\normalsize\gtfamily\bfseries 三角比の復習}
	\scriptsize
	{\normalsize\ajKaku{3}}~\ajKakko{1}\( x=6.8576\fallingdotseq 6.9 \)\ 
	\ajKakko{2}\( x=4.373\fallingdotseq 4.4 \)\ 
	\ajKakko{3}\( x=1.7008\fallingdotseq 1.7 \)\ 
	\ajKakko{4}\( x=5.0346\fallingdotseq 5.0 \)\ 
	\ajKakko{5}\( x=7.092\fallingdotseq 7.1 \)\ 
	\ajKakko{6}\( x=4.6025\fallingdotseq 4.6 \)\ 
	\ajKakko{7}\( x=7.94\fallingdotseq 7.9 \)\ 
	\ajKakko{8}\( x=18.65\fallingdotseq 18.7 \)
	}
\fi



\newpage %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%


\nidangumi{\subtoi
\begin{tikzpicture}[rotate=113, scale=0.26, baseline=(current bounding box.north)]
\coordinate [label=left:{\footnotesize A}] (A) at (5,12);
\coordinate [label=right:{\footnotesize B}] (B) at (0,0);
\coordinate [label=above:{\footnotesize C}] (C) at (5,0);
\draw (A)--(B)--(C)--cycle;
%\draw (4,0)--(4,1)--(5,1);
\draw (C)++(-0.7,0)-- ++(0,0.7)-- ++(0.7,0);
\draw(2.5,-0.5) node{\footnotesize $5$};
\draw(1,5) node{\footnotesize $13$};
\end{tikzpicture}\kotae{{5\over13},{12\over13},{5\over12}}
}
{\subtoi
\begin{tikzpicture}[rotate=0, scale=0.6, baseline=(current bounding box.north)]
\coordinate [label=left:{\footnotesize A}] (A) at (0,0);
\coordinate [label=right:{\footnotesize B}] (B) at (2,2.24);
\coordinate [label=right:{\footnotesize C}] (C) at (2,0);
\draw (A)--(B)--(C)--cycle;
%\draw (1.5,0)--(1.5,0.5)--(2,0.5);
\draw (C)++(-0.3,0)-- ++(0,0.3)-- ++(0.3,0);
\draw(1,-0.5) node{\footnotesize $2$};
\draw(2.3,1.3) node{\footnotesize $\sqrt{5}$};
\end{tikzpicture}\kotae{{\sqrt{5}\over3},{2\over3},{\sqrt{5}\over2}}
}

\vfill




\nidangumi{\subtoi
\begin{tikzpicture}[rotate=0, scale=0.3, baseline=(current bounding box.north)]
\coordinate [label=right:{\footnotesize A}] (A) at (6,0);
\coordinate [label=left:{\footnotesize B}] (B) at (0,5);
\coordinate [label=left:{\footnotesize C}] (C) at (0,0);
\draw (A)--(B)--(C)--cycle;
%\draw (0,0.5)--(0.5,0.5)--(0.5,0);
\draw (C)++(0.5,0)-- ++(0,0.5)-- ++(-0.5,0);
\draw(-0.5,2.5) node{\footnotesize $5$};
\draw(3,-0.5) node{\footnotesize $6$};
\end{tikzpicture}\kotae{
\ifyurika
	{5\sqrt{61}\over61},{6\sqrt{61}\over61},{5\over6}
\else
	{5\over\sqrt{61}},{6\over\sqrt{61}},{5\over6}
\fi}
}
{\subtoi
\begin{tikzpicture}[rotate=0, scale=0.4, baseline=(current bounding box.north)]
\coordinate [label=right:{\footnotesize A}] (A) at (3,0);
\coordinate [label=left:{\footnotesize B}] (B) at (0,5.2);
\coordinate [label=left:{\footnotesize C}] (C) at (0,0);
\draw (A)--(B)--(C)--cycle;
%\draw (0,0.5)--(0.5,0.5)--(0.5,0);
\draw (C)++(0.5,0)-- ++(0,0.5)-- ++(-0.5,0);
\draw(1.5,-0.5) node{\footnotesize $3$};
\draw(2,3) node{\footnotesize $6$};
\end{tikzpicture}\kotae{{\sqrt{3}\over2},{1\over2},\sqrt{3}}
}

\vfill


\toi 三角比の表を使って，次の値を調べなさい。\\
\ajKakko{1}\quad \makebox[18ex][l]{\(\sin 2^\circ\)}
\ajKakko{2}\quad \makebox[18ex][l]{\(\sin 61^\circ\)}
\ajKakko{3}\quad \makebox[18ex][l]{\(\cos 88^\circ\)}
\ajKakko{4}\quad \makebox[18ex][l]{\(\cos 35^\circ\)}
\\[8ex]
%\hspace*{-.3ex}
\ajKakko{5}\quad \makebox[18ex][l]{\(\cos 17^\circ\)}
\ajKakko{6}\quad \makebox[18ex][l]{\(\cos 31^\circ\)}
\ajKakko{7}\quad \makebox[18ex][l]{\(\sin 59^\circ\)}
\ajKakko{8}\quad \makebox[18ex][l]{\(\sin 73^\circ\)}\\[5ex]

\kotae{0.0349,~0.8746,~0.0349,~0.8192,~0.9563,~0.8572,~0.8572,~0.9563}


\newpage



\toi 次の直角三角形において，$x$の値をそれぞれ計算しなさい。\\
\hspace*{15zw}（小数第二位を四捨五入して，小数第一位まで求めなさい）

\bigskip

\nidangumi{\subtoi
\begin{tikzpicture}[rotate=0, scale=0.36, >=stealth, baseline=(current bounding box.north)]
\coordinate [label=left:{\footnotesize A}] (A) at (0,0);
\coordinate [label=right:{\footnotesize C}] (C) at ($ ({8*cos(31)},0) $);
\coordinate [label=right:{\footnotesize B}] (B) at ($ ({8*cos(31)},{8*sin(31)}) $);
\draw (A)--(B)--(C)--cycle;
\draw (C) ++(-0.3,0)-- ++(0,0.3) -- ++(0.3,0);
\draw(3.6,3) node{\footnotesize $8$};
%\draw(A)+(36pt,-12pt) node{\footnotesize $x$};
\draw(4,-0.5) node{\footnotesize $x$};
%\draw[<-](A)+(36pt,3pt)--(3,-1);
\draw(A)+(64pt,12pt) node{\footnotesize $31^\circ$};
\end{tikzpicture}\kotae{x=6.8576\fallingdotseq 6.9}
}
{\subtoi
\begin{tikzpicture}[rotate=0, scale=0.4, >=stealth, baseline=(current bounding box.north)]
\coordinate [label=left:{\footnotesize A}] (A) at (0,0);
\coordinate [label=below right:{\footnotesize C}] (C) at ($ ({5*cos(29)},0) $);
\coordinate [label=above right:{\footnotesize B}] (B) at ($ ({5*cos(29)},{5*sin(29)}) $);
\draw (A)--(B)--(C)--cycle;
\draw (C) ++(-0.5,0)-- ++(0,0.5) -- ++(0.5,0);
\draw(2.5,2) node{\footnotesize $5$};
\draw(2.5,-0.5) node{\footnotesize $x$};
\draw(A)+(50pt,12pt) node{\footnotesize $29^\circ$};
\end{tikzpicture}\kotae{x=4.373\fallingdotseq 4.4}
}

\vfill




\nidangumi{\subtoi
\begin{tikzpicture}[rotate=0, scale=0.4, >=stealth, baseline=(current bounding box.north)]
\coordinate [label=left:{\footnotesize A}] (A) at (0,0);
\coordinate [label=right:{\footnotesize C}] (C) at (8,0);
\coordinate [label=right:{\footnotesize B}] (B) at ($ (8,{8*tan(12)}) $);
\draw (A)--(B)--(C)--cycle;
\draw (C) ++(-0.5,0)-- ++(0,0.5) -- ++(0.5,0);
\draw(4,-0.5) node{\footnotesize $8$};
\draw($ (8+1,{8*tan(12)/2}) $) node{\footnotesize $x$};
\draw(A)+(100pt,12pt) node{\footnotesize $12^\circ$};
\end{tikzpicture}\kotae{x=1.7008\fallingdotseq 1.7}
}
{\subtoi
\begin{tikzpicture}[rotate=0, scale=0.35, >=stealth, baseline=(current bounding box.north)]
\coordinate [label=left:{\footnotesize A}] (A) at (0,0);
\coordinate [label=below right:{\footnotesize C}] (C) at ($ (6,0) $);
\coordinate [label=above right:{\footnotesize B}] (B) at ($ (6,{6*tan(40)}) $);
\draw (A)--(B)--(C)--cycle;
\draw (C) ++(-0.5,0)-- ++(0,0.5) -- ++(0.5,0);
\draw(3,-0.5) node{\footnotesize $6$};
\draw($ (6+1,{6*tan(40)/2}) $) node{\footnotesize $x$};
\draw(A)+(50pt,12pt) node{\footnotesize $40^\circ$};
\end{tikzpicture}\kotae{x=5.0346\fallingdotseq 5.0}
}

\vfill


\ifnum\make_pdf_with_insatsu>0
	\rotatebox{180}{{\normalsize\gtfamily\bfseries 三角比の復習}\scriptsize
	{\normalsize\ajKaku{1}}~
	\ajKakko{1}\( {3\over4},{\sqrt{7}\over4},
\ifyurika
	{3\sqrt{7}\over7} \)\ 
	\ajKakko{2}\( {5\sqrt{34}\over34},{3\sqrt{34}\over34},{5\over3} \)\ 
\else
	{3\over\sqrt{7}} \)\ 
	\ajKakko{2}\( {5\over\sqrt{34}},{3\over\sqrt{34}},{5\over3} \)\ 
\fi
	\ajKakko{3}\( {5\over13},{12\over13},{5\over12} \)\ 
	\ajKakko{4}\( {\sqrt{5}\over3},{2\over3},{\sqrt{5}\over2} \)
\ifyurika
	\ajKakko{5}\( {5\sqrt{61}\over61},{6\sqrt{61}\over61},{5\over6} \)
\else
	\ajKakko{5}\( {5\over\sqrt{61}},{6\over\sqrt{61}},{5\over6} \)
\fi
	\ajKakko{6}\( {\sqrt{3}\over2},{1\over2},\sqrt{3} \)
	{\normalsize\ajKaku{2}}~\ajKakko{1}\( 0.0349 \)\ 
	\ajKakko{2}\( 0.8746 \)\ 
	\ajKakko{3}\( 0.0349 \)\ 
	\ajKakko{4}\( 0.8192 \)
	\ajKakko{5}\( 0.9563 \)
	\ajKakko{6}\( 0.8572 \)
	\ajKakko{7}\( 0.8572 \)
	\ajKakko{8}\( 0.9563 \)
	}
\fi


\newpage



\nidangumi{\subtoi
\begin{tikzpicture}[rotate=0, scale=0.3, >=stealth, baseline=(current bounding box.north)]
\coordinate [label=left:{\footnotesize A}] (A) at (0,0);
\coordinate [label=right:{\footnotesize C}] (C) at ($ ({9*cos(52)},0) $);
\coordinate [label=right:{\footnotesize B}] (B) at ($ ({9*cos(52)},{9*sin(52)}) $);
\draw (A)--(B)--(C)--cycle;
\draw (C) ++(-0.5,0)-- ++(0,0.5) -- ++(0.5,0);
\draw(2.5,4) node{\footnotesize $9$};
\draw($ ({9*cos(52)+0.5},{9*sin(52)/2}) $) node{\footnotesize $x$};
\draw(A)+(48pt,12pt) node{\footnotesize $52^\circ$};
\end{tikzpicture}\kotae{x=7.092\fallingdotseq 7.1}
}
{\subtoi
\begin{tikzpicture}[rotate=0, scale=0.5, >=stealth, baseline=(current bounding box.north)]
\coordinate [label=left:{\footnotesize A}] (A) at (0,0);
\coordinate [label=below right:{\footnotesize C}] (C) at ($ ({5*cos(23)},0) $);
\coordinate [label=above right:{\footnotesize B}] (B) at ($ ({5*cos(23)},{5*sin(23)}) $);
\draw (A)--(B)--(C)--cycle;
\draw (C) ++(-0.5,0)-- ++(0,0.5) -- ++(0.5,0);
\draw(2.5,2) node{\footnotesize $5$};
\draw(2,-0.5) node{\footnotesize $x$};
\draw(A)+(50pt,6pt) node{\footnotesize $23^\circ$};
\end{tikzpicture}\kotae{x=4.6025\fallingdotseq 4.6}
}

\vfill


\nidangumi{\subtoi
\begin{tikzpicture}[rotate=0, scale=0.4, >=stealth, baseline=(current bounding box.north)]
\coordinate [label=left:{\footnotesize A}] (A) at (0,0);
\coordinate [label=right:{\footnotesize C}] (C) at ($ ({8*cos(83)},0) $);
\coordinate [label=right:{\footnotesize B}] (B) at ($ ({8*cos(83)},{8*sin(83)}) $);
\draw (A)--(B)--(C)--cycle;
\draw (C) ++(-0.2,0)-- ++(0,0.2) -- ++(0.2,0);
\draw(0,5) node{\footnotesize $8$};
\draw($ ({8*cos(83)+1},{8*sin(83)/2}) $) node{\footnotesize $x$};
\draw(A)+(12pt,12pt) node{\footnotesize $83^\circ$};
\end{tikzpicture}\kotae{x=7.94\fallingdotseq 7.9}
}
{\subtoi
\begin{tikzpicture}[rotate=0, scale=0.08, >=stealth, baseline=(current bounding box.north)]
\coordinate [label=left:{\footnotesize A}] (A) at (0,0);
\coordinate [label=right:{\footnotesize C}] (C) at (20,0);
\coordinate [label=right:{\footnotesize B}] (B) at ($ (20,{20*tan(43)}) $);
\draw (A)--(B)--(C)--cycle;
\draw (C) ++(-3,0)-- ++(0,3) -- ++(3,0);
\draw(10,-2) node{\footnotesize $20$};
\draw($ (20+2,{20*tan(43)/2}) $) node{\footnotesize $x$};
\draw(A)+(200pt,50pt) node{\footnotesize $43^\circ$};
\end{tikzpicture}\kotae{x=18.65\fallingdotseq 18.7}
}


\vfill


\end{document}
