%
%	gbb60166@gmail.com	https://unilab.gbb60166.jp/prekou/prekou.htm
%
% aspectratio= は 1610, 169, 149, 54, 32 の中から選べる（省略時は 43）
% C:\texlive\2023\texmf-dist\tex\latex\beamer\beamer.cls
%\documentclass[17pt,dvipdfmx,hyperref={pdfpagemode=FullScreen},aspectratio=169]{beamer}
%\documentclass[17pt,dvipdfmx,hyperref={pdfstartview={XYZ null null 8.00}},aspectratio=169]{beamer}
\documentclass[17pt,dvipdfmx,aspectratio=169]{beamer}
% pdfの栞の字化けを防ぐ
%\AtBeginDvi{\special{pdf:tounicode EUC-UCS2}}
% テーマ
\usetheme{Copenhagen}
% navi. symbolsは目立たないが，dvipdfmxを使うと機能しないので非表示に
\setbeamertemplate{navigation symbols}{} 
\usepackage{bxdpx-beamer,pxjahyper,minijs}
%\usepackage{graphicx}
%\usepackage{tkokugo,furikana,tsayusen,shiika,sfkanbun,jdkintou,plext}
%\usepackage{type1cm}
\usepackage[deluxe]{otf}
%\usepackage{tikzsymbols}
%\usepackage[dvipdfmx]{graphicx}%
\def\pgfsysdriver{pgfsys-dvipdfmx.def}%（graphicxパッケージを使用しない場合はこの行を有効に）
%\def\pgfsysdriver{pgfsys-dvips.def}%デフォルト
%\usepackage[e]{esvect}
\usepackage{tikz}%（これで、pgfとpgfforが読み込まれます。）
%\usepackage{tikz-3dplot}
\usetikzlibrary{calc,angles,quotes,intersections}
%\usetikzlibrary{arrows.meta,patterns,backgrounds}
%\usepackage{animate}
%\usepackage{pgfplots}
%\pgfplotsset{compat=newest}
%\pgfplotsset{compat=newest, every axis/.append style={line width=1pt}}
%\PassOptionsToPackage{dvipdfmx}{graphicx}
\nofiles

% フォントはお好みで
%\usepackage{txfonts}

\mathversion{bold}
\renewcommand{\familydefault}{\sfdefault}
\renewcommand{\seriesdefault}{bx}
\renewcommand{\kanjifamilydefault}{\gtdefault}
\renewcommand{\kanjiseriesdefault}{bx}
\setbeamerfont{title}{size=\normalsize,series=\bfseries}
\setbeamerfont{frametitle}{size=\normalsize,series=\bfseries}
\setbeamertemplate{frametitle}[default][center]
\usefonttheme{professionalfonts}

% 参考にしたURL
% http://windom.phys.hirosaki-u.ac.jp/fswiki/wiki.cgi?page=LaTeX+Beamer%A4%C7%A5%D7%A5%EC%A5%BC%A5%F3%A5%C6%A1%BC%A5%B7%A5%E7%A5%F3

\newcommand{\Slash}[1]{\ooalign{\hfil\kern-3pt／\hfil\crcr$#1$}}
\everymath{\displaystyle}

\def\maruwaku#1{\begin{tikzpicture}[scale=0.7, baseline={([yshift=-22pt] current bounding box.north)}]
\filldraw[color=CUDBlue, line width=1pt, rounded corners=2pt] (-0.1,0)--(2.1,0)--(2.1,1.1)--(-0.1,1.1)--cycle;
\draw(1,0.5) node[white]{#1};
\end{tikzpicture}
}

\setbeamersize{text margin left=5mm,text margin right=5mm}
\fboxrule=0.8pt

\makeatletter
\def\hooklen#1#2{\settowidth{\@tempdima}{\(#1\)}
%\advance\@tempdima by.3ex
% ↑ 数式モードで式の前後に入るスペースを制御したかったが、
%    難しいのでやめた。段々難解なコードになっているのでやめた方がよい？
\hbox to\@tempdima{\hfil \(#2\)\hfil}}
%■等号付き不等号 by 美文書作成入門
\newcommand{\myleqq}{\mathrel{\mathpalette\gl@align<}}
\newcommand{\mygeqq}{\mathrel{\mathpalette\gl@align>}}
\newcommand{\gl@align}[2]{\lower.6ex\vbox{\baselineskip\z@skip\lineskip\z@
	\ialign{$\m@th#1\hfil##\hfil$\crcr#2\crcr=\crcr}}}
\makeatother

% カラーユニバーサルデザインを調べたつもりだがあまり自信がありません
% http://www.fukushihoken.metro.tokyo.jp/kiban/machizukuri/kanren/color.files/colorudguideline.pdf
% http://jfly.iam.u-tokyo.ac.jp/colorset/

% ■ アクセントカラー小面積を目立たせる高彩度色
\definecolor{CUDRed}{RGB}{255,75,0}
\definecolor{CUDGreen}{RGB}{3,175,122}
\definecolor{CUDBlue}{RGB}{0,90,255}
\definecolor{CUDCyan}{RGB}{77,196,255}
\definecolor{CUDMagenta}{RGB}{153,0,153}
\definecolor{CUDYellow}{RGB}{255,241,0}
\definecolor{CUDBrown}{RGB}{128,64,0}

\definecolor{CUDOrange}{RGB}{246,170,0}

% ■ ベースカラー広い面積の塗り分けに用いる低・中彩度色
\definecolor{CUDPink}{RGB}{255,202,191}
\definecolor{CUDBrightGreen}{RGB}{119,217,168}
\definecolor{CUDLime}{RGB}{216,242,85}
\definecolor{CUDCream}{RGB}{255,255,128}
\definecolor{CUDBrightCyan}{RGB}{191,228,255}
%\definecolor{CUD}{RGB}{}%

\setbeamercolor{CUDBrightGreen}{fg=black,bg=CUDBrightGreen!50}
\setbeamercolor{CUDCream}{fg=black,bg=CUDCream!75}



\begin{document}

\title{数学}\author{高校}

%■■■■■■■■■■■■■　テスト領域　■■■■■■■■■■■■■■



%\end{document}
%■■■■■■■■■■■■■　完成品　■■■■■■■■■■■■■■

\begin{frame}[t]
\frametitle{角度は何度？}
\begin{minipage}[t]{0.48\textwidth}
\begin{tikzpicture}[scale=1.5, very thick,
	baseline=(current bounding box.north)]
\coordinate (O) at (0,0);
\coordinate (A) at (2.7,1);
\coordinate (B) at (4.3,0.8);
\coordinate (C) at (2.5,2.3);
\coordinate (D) at ($ (C)!2!(A) $);

\pic["\( 150^\circ \)", draw=black, -, 
	angle eccentricity=1.8, angle radius=9pt] {angle=O--A--B};

\alt<-5>{\pic["\( 30^\circ \)", draw=black, -, 
	angle eccentricity=1.8, angle radius=16pt] {angle=C--B--A};}
	{\pic["\textcolor{CUDBlue}{\( 30^\circ \)}", 
	fill=CUDBlue, -, angle eccentricity=1.8, angle radius=16pt]
		{angle=C--B--A};
	}

\pic["\( x \)", draw=black, -, angle eccentricity=1.8,
	angle radius=12pt]{angle=O--C--B};
\alt<-3>{\pic["\( 20^\circ \)", draw=black, -,
	angle eccentricity=1.8, angle radius=20pt] {angle=A--O--C};}
	{\pic["\textcolor{CUDRed}{\( 20^\circ \)}", 
	fill=CUDRed, -, angle eccentricity=1.8, angle radius=20pt]
	{angle=A--O--C};
	}

\visible<4->{\pic["\textcolor{CUDRed}{\( a \)}", draw=CUDRed, -, 
	angle eccentricity=1.5, angle radius=20pt] {angle=O--C--A};
	}
\visible<5->{\pic["\kern-16pt\textcolor{CUDRed}{\( a+20 \)}", draw=CUDRed, -,
	angle eccentricity=1.8, angle radius=20pt] {angle=O--A--D};
	}
\visible<6->{\pic["\textcolor{CUDBlue}{\( b \)}", draw=CUDBlue, -,
	angle eccentricity=1.5, angle radius=16pt] {angle=A--C--B};
	}
\visible<7->{\pic["\kern24pt\textcolor{CUDBlue}{\( b+30 \)}", draw=CUDBlue, -,
	angle eccentricity=1.8, angle radius=24pt] {angle=D--A--B};
	}
\draw[line join=round] (O)--(A)--(B)--(C)--(O)--cycle;
\visible<2->{\draw[CUDGreen,line width=2pt](C)--(D);}
\end{tikzpicture}
\end{minipage}
\hspace*{1ex}
\begin{minipage}[t]{0.44\textwidth}
\only<3>{「三角形の外角は、その外角に隣り合わない$2$つの内角の和に等しい」ので}
\only<8->{\centerline{%
	\( \textcolor{CUDRed}{a\!+\!20}+\textcolor{CUDBlue}{b\!+\!30}=150 \)}
	}

\bigskip
\only<9->{\centerline{\( a+b+50=150 \)}}

\bigskip
\only<10->{\centerline{\( x+50=150 \)}}

\bigskip
\only<11->{\centerline{\( x=100^\circ \)\quad\□答}}
\end{minipage}
\end{frame}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

\begin{frame}[t]
\frametitle{角度は何度？}
\begin{minipage}[t]{0.48\textwidth}
\begin{tikzpicture}[scale=1, very thick, baseline=(current bounding box.north)]
\coordinate (A) at (0.3,0);
\coordinate (B) at (6.2,-1.1);
\coordinate (C) at (5.6,3.7);
\coordinate (E) at (0,3.1);
\coordinate (D) at (2.8,3.4);

\alt<3->{\pic["\footnotesize\textcolor{CUDRed}{\( 40^\circ \)}", 
	fill=CUDRed, -, angle eccentricity=1.8, angle radius=12pt]
		{angle=B--E--D};
	\pic["\footnotesize\textcolor{CUDRed}{\( 20^\circ \)}", 
		fill=CUDRed, -, angle eccentricity=1.5, angle radius=24pt]
		{angle=D--B--E};}
	{\pic["\footnotesize\( 40^\circ \)", draw=black, -, 
		angle eccentricity=1.8, angle radius=12pt] {angle=B--E--D};
	\pic["\footnotesize\( 20^\circ \)", draw=black, -, 
		angle eccentricity=1.5, angle radius=24pt] {angle=D--B--E};
	}
\visible<4->{\pic["\footnotesize\textcolor{CUDRed}{\( 60^\circ \)}", 
		fill=CUDRed, -, angle eccentricity=2, angle radius=12pt]
		{angle=B--D--C};
	}

\alt<5->{\pic["\footnotesize\textcolor{CUDBlue}{\( 15^\circ \)}", 
	fill=CUDBlue, -, angle eccentricity=1.8, angle radius=20pt]
		{angle=C--A--D};
	\pic["\footnotesize\textcolor{CUDBlue}{\( 30^\circ \)}", 
	fill=CUDBlue, -, angle eccentricity=1.8, angle radius=12pt]
		{angle=E--C--A};
	}
	{\pic["\footnotesize\( 15^\circ \)", draw=black, -,
		angle eccentricity=1.8, angle radius=20pt] {angle=C--A--D};
	\pic["\footnotesize\( 30^\circ \)", draw=black, -,
		angle eccentricity=1.8, angle radius=12pt] {angle=E--C--A};
	}

\visible<6->{\pic["\footnotesize\textcolor{CUDBlue}{\( 45^\circ \)}",
	fill=CUDBlue, -, angle eccentricity=2, angle radius=16pt]
		{angle=E--D--A};
	}
\draw[line join=round] (D)--(A)--(C)--(E)--(B)--cycle;
\pic["\( x \)", draw=black, -, angle eccentricity=1.8, angle radius=9pt]
	{angle=A--D--B};
\end{tikzpicture}
\end{minipage}
\hspace*{1ex}
\begin{minipage}[t]{0.44\textwidth}
\only<2>{「三角形の外角は、その外角に隣り合わない$2$つの内角の和に等しい」ので}

\only<7->{一直線は\( 180^\circ \)なので}

\bigskip
\only<8->{\centerline{\( \textcolor{CUDBlue}{45}+x+
	\textcolor{CUDRed}{60}=180 \)}
	}

\bigskip
\only<9->{\centerline{\( x+105=180 \)}}

\bigskip
\only<10->{\centerline{\( x=75^\circ \)\quad\□答}}
\end{minipage}
\end{frame}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

\begin{frame}[t]
\frametitle{角度は何度？}
\begin{minipage}[t]{0.48\textwidth}
\begin{tikzpicture}[scale=1.2, very thick,
	baseline=(current bounding box.north)]
\coordinate (O) at (0,0) node [below] at (O) {\small O};
\coordinate (A) at (-70:2);
\coordinate (B) at (2,0);
\coordinate (C) at (60:2);
\coordinate (D) at (-2,0);

\alt<5->{\pic["\textcolor{CUDBlue}{\( x \)}", fill=CUDBlue, -,
	angle eccentricity=1.8, angle radius=9pt] {angle=C--B--D};}
	{\pic["\( x \)", draw=black, -, angle eccentricity=1.8, 
	angle radius=9pt] {angle=C--B--D};
	}
\visible<2->{\draw[CUDGreen](O)--(C);}
\visible<4->{\pic["\footnotesize\textcolor{CUDRed}{\( 60^\circ \)}", 
	fill=CUDRed, -, angle eccentricity=1.8, angle radius=12pt]
	{angle=B--O--C};
	}
\draw (O) circle (2);
\draw[line join=round] (D)--(B)--(C)--(A)--(B);
\fill (O) circle (1.5pt);

\visible<5->{\draw[CUDGreen](O)--(C)--(B)--cycle;
	\pic["\textcolor{CUDBlue}{\( x \)}", fill=CUDBlue, -, 
	angle eccentricity=1.8, angle radius=9pt] {angle=O--C--B};
	\draw[CUDGreen](0:1.2) node[rotate=90]{＝};
	\draw[CUDGreen](60:1.2) node[rotate=150]{＝};
	}
\alt<3->{\pic["\footnotesize\textcolor{CUDRed}{\( 30^\circ \)}", 
		fill=CUDRed, -, angle eccentricity=1.8, angle radius=12pt]
	{angle=B--A--C};}
	{\pic["\footnotesize\( 30^\circ \)", draw=black, -,
	angle eccentricity=1.8, angle radius=12pt] {angle=B--A--C};
	}
\end{tikzpicture}
\end{minipage}
\hspace*{1ex}
\begin{minipage}[t]{0.44\textwidth}
\only<3>{中心角は円周角の$2$倍なので}
\only<5>{二等辺三角形なので、底角は等しい}
\only<6->{三角形の内角の和は\\\( 180^\circ \)なので\\[1ex]
	\centerline{\( \textcolor{CUDBlue}{2x}+\textcolor{CUDRed}{60}=180 \)}
	\\[1ex]
	}
\only<7->{\centerline{\( 2x=120 \)}}

\bigskip
\only<8->{\centerline{\( x=60^\circ \)\quad\□答}}
\end{minipage}
\end{frame}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

\begin{frame}[t]
\frametitle{角度は何度？}
\begin{minipage}[t]{0.48\textwidth}
\begin{tikzpicture}[scale=1.5, very thick,
	baseline=(current bounding box.north)]
\coordinate (O) at (0,0);
\coordinate (A) at (2.4,-0.1);
\coordinate (B) at (3.7,3.5);
\coordinate (C) at (0.5,3.2);

\path [name path=O--B](O)--(B);
\path [name path=A--C](A)--(C);
\path [name intersections={of=O--B and A--C, by=X}];

\alt<3->{\pic["\footnotesize\textcolor{CUDRed}{\( 50^\circ \)}", 
		fill=CUDRed, -, angle eccentricity=2, %
		angle radius=15pt] {angle=B--A--C};
	\pic["\footnotesize\textcolor{CUDRed}{\( 30^\circ \)}", 
		fill=CUDRed, -, angle eccentricity=2, %
		angle radius=18pt] {angle=O--B--A};}
	{\pic["\footnotesize\( 50^\circ \)", draw=black, -, 
		angle eccentricity=2, angle radius=15pt] {angle=B--A--C};
	\pic["\footnotesize\( 30^\circ \)", draw=black, -, 
		angle eccentricity=2, angle radius=18pt] {angle=O--B--A};
	}

\pic["\( x \)", draw=black, -, angle eccentricity=2, angle radius=15pt]
	{angle=B--O--C};
\pic["\footnotesize\( 45^\circ \)", draw=black, -, angle eccentricity=2,
	angle radius=15pt] {angle=O--C--A};

\visible<4->{\pic["\kern6pt\footnotesize\textcolor{CUDGreen}{\( 100^\circ \)}",
		 fill=CUDGreen, -, angle eccentricity=2, %
		angle radius=12pt] {angle=A--X--B};
	}
\visible<6->{\pic["\kern-6pt\footnotesize\textcolor{CUDGreen}
		{\( 100^\circ \)}", fill=CUDGreen, -, angle eccentricity=2,
		angle radius=12pt] {angle=C--X--O};
	}

\draw[line join=round] (O)--(B)--(A)--(C)--(O)--cycle;
\end{tikzpicture}
\end{minipage}
\hspace*{1ex}
\begin{minipage}[t]{0.44\textwidth}
\only<2-4,7->{三角形の内角の和は\\\( 180^\circ \)なので}
\only<5>{対頂角は等しいので}

\bigskip
\only<8->{\centerline{\( x+45+\textcolor{CUDGreen}{100}=180 \)}}

\bigskip
\only<9->{\centerline{\( x=35^\circ \)\quad\□答}}
\end{minipage}
\end{frame}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

\begin{frame}[t]
\frametitle{角度は何度？}
\begin{minipage}[t]{0.48\textwidth}
\begin{tikzpicture}[scale=1.1, very thick,
	baseline=(current bounding box.north)]
\coordinate (O) at (0,0);
\coordinate (A) at (6,0);
\coordinate (B) at (0,3.1);
\coordinate (C) at (6,3.1);
\coordinate (D) at (3.8,0);
\coordinate (E) at (5.1,1.3);
\coordinate (F) at (4.5,2.5);
\coordinate (G) at (2.3,3.1);

\coordinate (LE) at (4.1,1.3);
\coordinate (RE) at (6.1,1.3);
\coordinate (LF) at (3,2.5);
\coordinate (RF) at (5.5,2.5);

\alt<2->{\pic["\footnotesize\textcolor{CUDRed}{\( 145^\circ \)}", 
		fill=CUDRed, -, angle eccentricity=2, %
		angle radius=8pt] {angle=E--D--O};}
	{\pic["\footnotesize\( 145^\circ \)", draw=black, -, 
		angle eccentricity=2, angle radius=8pt] {angle=E--D--O};
	}

\pic["\footnotesize\( 100^\circ \)", draw=black, -, angle eccentricity=2.4, 
	angle radius=8pt] {angle=F--E--D};
\pic["\( x \)", draw=black, -, angle eccentricity=1.8, angle radius=8pt]
	{angle=G--F--E};
\pic["\footnotesize\( 160^\circ \)", draw=black, -, angle eccentricity=2, 
	angle radius=8pt] {angle=B--G--F};

\visible<2->{\draw[CUDGreen](LE)--(RE);
	\draw[CUDGreen](LF)--(RF);
	}
\visible<3->{\pic["\footnotesize\textcolor{CUDRed}{\( 145^\circ \)}", 
	fill=CUDRed, -, angle eccentricity=2, %
		angle radius=8pt] {angle=D--E--RE};
	}
\visible<5->{\pic["\footnotesize\textcolor{CUDBlue}{\( 115^\circ \)}", 
	fill=CUDBlue, -, angle eccentricity=2, %
		angle radius=8pt] {angle=RE--E--F};
	}
\visible<7->{\pic["\footnotesize\textcolor{CUDBlue}{\( 115^\circ \)}", 
	draw=CUDBlue, -, angle eccentricity=2, %
		angle radius=12pt] {angle=LF--F--E};
	}
\visible<9->{\pic["\footnotesize\textcolor{CUDGreen}{\( 20^\circ \)}", 
	fill=CUDGreen, -, angle eccentricity=1.8, %
		angle radius=24pt] {angle=F--G--C};
	}
\visible<11->{\pic["\footnotesize\textcolor{CUDGreen}{\( 20^\circ \)}", 
	draw=CUDGreen, -, angle eccentricity=1.8, %
		angle radius=24pt] {angle=G--F--LF};
	}
\draw[line join=round](D)--(E)--(F)--(G);
\draw (O)--(A);
\draw (B)--(C);
\footnotesize
\draw(6.4,0) node{$m$};
\draw(6.4,3.1) node{$l$};
\draw(0.5,1.5) node{$l/\!/m$};
\end{tikzpicture}
\end{minipage}
%\hspace*{1ex}
\begin{minipage}[t]{0.44\textwidth}
\only<2,6,10>{錯角は等しいので}
\only<4>{一周は\( 360^\circ \)なので}
\only<8>{一直線は\( 180^\circ \)なので}

\bigskip
\only<12->{\centerline{\( x = \textcolor{CUDGreen}{20}
	+ \textcolor{CUDBlue}{115} \)}
	}

\bigskip
\only<13->{\centerline{\( x=135^\circ \)\quad\□答}}
\end{minipage}
\end{frame}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

\begin{frame}[t]
\frametitle{角度は何度？}
\begin{minipage}[t]{0.48\textwidth}
\begin{tikzpicture}[scale=1.2, very thick,
	baseline=(current bounding box.north)]
\coordinate (O) at (0,0);
\coordinate (A) at (5,0);
\coordinate (B) at (0,2.6);
\coordinate (C) at (5,2.6);
\coordinate (D) at (2.1,0);
\coordinate (E) at (4.4,3.7);
\coordinate (F) at (1,2.6);

\path [name path=B--C](B)--(C);
\path [name path=D--E](D)--(E);
\path [name intersections={of=B--C and D--E, by=X}];

\draw(5.4,0) node{\footnotesize $m$};
\draw(5.4,2.6) node{\footnotesize $l$};
\draw(0.5,1) node{\footnotesize $l/\!/m$};

\alt<4->{\pic["\footnotesize\textcolor{CUDBlue}{\( 58^\circ \)}",
		fill=CUDBlue, -, angle eccentricity=2, %
		angle radius=12pt] {angle=A--D--E};}
	{\pic["\footnotesize\( 58^\circ \)", draw=black, -, 
		angle eccentricity=2, angle radius=12pt] {angle=A--D--E};
	}

\alt<2->{\pic["\textcolor{CUDRed}{\( x \)}", fill=CUDRed, -,
		angle eccentricity=2, angle radius=12pt] {angle=F--E--D};
	\pic["\footnotesize\textcolor{CUDRed}{\( 21^\circ \)}",
		fill=CUDRed, -, angle eccentricity=2, %
		angle radius=20pt] {angle=C--F--E};}
	{\pic["\( x \)", draw=black, -, angle eccentricity=2, 
		angle radius=12pt] {angle=F--E--D};
	\pic["\footnotesize\( 21^\circ \)", draw=black, -, 
		angle eccentricity=2, angle radius=20pt] {angle=C--F--E};
	}

\visible<3->{\pic["\kern-16pt\footnotesize\textcolor{CUDRed}{\( 21+x \)}", 
	draw=CUDRed, -, angle eccentricity=1.5, %
	angle radius=28pt] {angle=B--X--D};
	}
\visible<5->{\pic["\footnotesize\textcolor{CUDBlue}{\( 58^\circ \)}", 
		fill=CUDBlue, -, angle eccentricity=2, %
		angle radius=9pt] {angle=B--X--D};
	}

\draw[line join=round](D)--(E)--(F);
\draw (O)--(A);
\draw (B)--(C);
\end{tikzpicture}
\end{minipage}
\hspace*{1ex}
\begin{minipage}[t]{0.44\textwidth}
\only<2>{「三角形の外角は、その外角に隣り合わない$2$つの内角の和に等しい」ので}
\only<4>{錯角は等しいので}

\bigskip
\only<6->{\centerline{\( \textcolor{CUDRed}{21+x}=\textcolor{CUDBlue}{58} \)}}

\bigskip
\only<7->{\centerline{\( x=37^\circ \)\quad\□答}}
\end{minipage}
\end{frame}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

\begin{frame}[t]
\frametitle{角度は何度？}
\begin{minipage}[t]{0.48\textwidth}
\begin{tikzpicture}[scale=1.8, >=stealth, very thick,
	baseline=(current bounding box.north)]
\coordinate (O) at (0,0) node [above] at (O) {\small O};
\coordinate (A) at (-130:1.6);
\coordinate (B) at (-40:1.6);
\coordinate (C) at (10:1.6);

\path [name path=A--C](A)--(C);
\path [name path=O--B](O)--(B);
\path [name intersections={of=A--C and O--B, by=X}];

\draw (O) circle (1.6);
\fill (O) circle (1.5pt);
\draw [->] (-0.8,-0.2)--(-0.8,-1.05);

\draw(-0.8,0) node{\footnotesize $18^\circ$};

\alt<2->{\pic["\tiny\textcolor{CUDRed}{\( 100^\circ \)}", fill=CUDRed, -, 
		angle eccentricity=1.5, %
		angle radius=9pt] {angle=A--O--B};}
	{\pic["\tiny\( 100^\circ \)", draw=black, -, angle eccentricity=1.5, 
		angle radius=9pt] {angle=A--O--B};
	}

\pic[draw=black, -, angle eccentricity=1.5, angle radius=20pt]
	{angle=C--A--O};
\pic["\tiny\( x \)", draw=black, -, angle eccentricity=1.5, angle radius=9pt]
	{angle=A--C--B};
\pic["\tiny\( y \)", draw=black, -, angle eccentricity=1.5, angle radius=9pt]
	{angle=C--B--O};

\visible<3->{\pic["\footnotesize\textcolor{CUDRed}{\( 50^\circ \)}", 
		draw=CUDRed, -, angle eccentricity=2,
		angle radius=16pt] {angle=A--C--B};
	}
\visible<5->{\pic["\footnotesize\textcolor{CUDBlue}{\( 62^\circ \)}", 
		draw=CUDBlue, -, angle eccentricity=2, %
		angle radius=9pt] {angle=O--X--A};
	}
\visible<7->{\pic["\footnotesize\textcolor{CUDBlue}{\( 62^\circ \)}", 
		draw=CUDBlue, -, angle eccentricity=2.2,
		angle radius=9pt] {angle=B--X--C};
	}
\draw[line join=round] (O)--(B)--(C)--(A)--(O);
\visible<4->{\draw[CUDGreen](O)--(A)--(X)--cycle;}
\end{tikzpicture}
\end{minipage}
\hspace*{1ex}
\begin{minipage}[t]{0.44\textwidth}
\only<2>{中心角は円周角の$2$倍なので}
\only<4,8>{三角形の内角の和は\\\( 180^\circ \)なので}
\only<6-7>{対頂角は等しいので}

\bigskip
\only<9->{\centerline{\( y+\textcolor{CUDRed}{50}
	+\textcolor{CUDBlue}{62}=180 \)}}

\bigskip
\only<10->{\centerline{\( y+112=180 \)}}

\bigskip
\only<11->{\centerline{\( y=68^\circ \)\quad\□答}}
\end{minipage}
\end{frame}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

\begin{frame}[t]
\frametitle{角度は何度？}
\begin{minipage}[t]{0.48\textwidth}
\begin{tikzpicture}[scale=1.5, >=stealth, very thick, 
	baseline=(current bounding box.north)]
\coordinate (A) at (0.4,2.9);
\coordinate (B) at (4.1,0.1);
\coordinate (C) at (0,0);
\coordinate (D) at (3,2.7);

\path [name path=A--B](A)--(B);
\path [name path=C--D](C)--(D);
\path [name intersections={of=A--B and C--D, by=X}];

\alt<2->{\pic["\kern3pt\footnotesize\textcolor{CUDRed}{\( 40^\circ \)}", 
		fill=CUDRed, -, angle eccentricity=2, angle radius=12pt]
		{angle=D--C--A};
	\pic["\footnotesize\textcolor{CUDRed}{\( 60^\circ \)}", fill=CUDRed, 
		-, angle eccentricity=1.5, angle radius=12pt] {angle=C--A--B};
	}
	{\pic["\kern3pt\footnotesize\( 40^\circ \)", draw=black, -, 
		angle eccentricity=2, angle radius=12pt] {angle=D--C--A};
	\pic["\footnotesize\( 60^\circ \)", draw=black, -, 
		angle eccentricity=1.5, angle radius=12pt] {angle=C--A--B};
	}

\pic["\footnotesize\( 70^\circ \)", draw=black, -, angle eccentricity=1.5, 
	angle radius=12pt] {angle=C--D--B};
\pic["\( x \)", draw=black, -, angle eccentricity=2, angle radius=12pt]
	{angle=D--B--A};
\visible<2->{\draw[CUDGreen](X)--(A)--(C)--cycle;}
\visible<3->{\pic["\footnotesize\textcolor{CUDBlue}{\( 80^\circ \)}", 
	fill=CUDBlue, -, angle eccentricity=2, %
	angle radius=12pt] {angle=A--X--C};
	}
\visible<5->{\pic["\footnotesize\textcolor{CUDBlue}{\( 80^\circ \)}", 
		fill=CUDBlue, -, angle eccentricity=2, %
		angle radius=12pt] {angle=B--X--D};
	}
\draw[line join=round](A)--(C)--(D)--(B)--cycle;
\end{tikzpicture}
\end{minipage}
\hspace*{1ex}
\begin{minipage}[t]{0.44\textwidth}
\only<2-3,6->{三角形の内角の和は\\\( 180^\circ \)なので}
\only<4>{対頂角は等しいので}

\bigskip
\only<7->{\centerline{\( x+70+\textcolor{CUDBlue}{80}=180 \)}}

\bigskip
\only<8->{\centerline{\( x+150=180 \)}}

\bigskip
\only<9->{\centerline{\( x=30^\circ \)\quad\□答}}
\end{minipage}
\end{frame}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

\begin{frame}[t]
\frametitle{角度は何度？}
\begin{minipage}[t]{0.48\textwidth}
\begin{tikzpicture}[scale=1.5, >=stealth, very thick,
	baseline=(current bounding box.north)]
\coordinate (O) at (0,0) node [left] at (O) {\small O};
\coordinate (A) at (-135:2);
\coordinate (B) at (10:2);
\coordinate (C) at (120:2);

\draw (O) circle (2);
\draw[line join=round] (O)--(A)--(B)--(C)--cycle;
\fill (O) circle (1.5pt);

\pic["\footnotesize\( 240^\circ \)", draw=black, -, angle eccentricity=3, 
	angle radius=9pt] {angle=A--O--C};
\pic["\( x \)", draw=black, -, angle eccentricity=1.5, angle radius=16pt]
	{angle=C--B--A};

\visible<3->{\pic["\footnotesize\textcolor{CUDRed}{\( 120^\circ \)}", 
		draw=CUDRed, -, angle eccentricity=1.8, %
		angle radius=20pt] {angle=C--O--A};
	}
\visible<5->{\pic["\footnotesize\textcolor{CUDRed}{\( 60^\circ \)}", 
		draw=CUDRed, -, angle eccentricity=1.4, %
		angle radius=36pt] {angle=C--B--A};
	}
\end{tikzpicture}
\end{minipage}
\hspace*{1ex}
\begin{minipage}[t]{0.44\textwidth}
\only<2-3>{一周は\( 360^\circ \)なので}
\only<4-5>{中心角は円周角の$2$倍なので}
\end{minipage}
\end{frame}
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%




\end{document}
